F(200)=5*(2)^x

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Solution for F(200)=5*(2)^x equation: 



(200)=5(2)^F

We move all terms to the left:

(200)-(5(2)^F)=0

determiningTheFunctionDomain
-52^F+200=0

We move all terms containing F to the left, all other terms to the right

-52^F=-200

F=-200/1

F=-200

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